The area bounded by the curve y=f(x) and the lines x=0, y=0 and x=t lies in the interval if it is given that the polynomial f(x) = 1 + 2x + 3x^2 + 4x^3. Let s be the sum of all distinct real roots of f(x) and let t=|s|

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Sher Mohammad · Answer

sum of roots, s =-3/4 |s|=.75 area =integration f(x) dx between o to .75 =[x^4+x^3+x^2+x ], between 0 and .75 , is 2.05 sher mohammad askiitians faculty b.tech, iit delhi

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The area bounded by the curve y=f(x) and the lines x=0, y=0 and x=t lies in the interval if it is given that the polynomial f(x) = 1 + 2x + 3x^2 + 4x^3. Let s be the sum of all distinct real roots of f(x) and let t=|s|

The area bounded by the curve y=f(x) and the lines x=0, y=0 and x=t lies in the interval if it is given that the polynomial f(x) = 1 + 2x + 3x^2 + 4x^3. Let s be the sum of all distinct real roots of f(x) and let t=|s|

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The area bounded by the curve y=f(x) and the lines x=0, y=0 and x=t lies in the interval if it is given that the polynomial f(x) = 1 + 2x + 3x^2 + 4x^3. Let s be the sum of all distinct real roots of f(x) and let t=|s|

The area bounded by the curve y=f(x) and the lines x=0, y=0 and x=t lies in the interval if it is given that the polynomial f(x) = 1 + 2x + 3x^2 + 4x^3. Let s be the sum of all distinct real roots of f(x) and let t=|s|

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