Suppose x 1 & x 2 are the point of maximum and the point of minimum respectively of the function f(x) = 2x 3 – 9ax 2 + 12a 2 x + 1 respectively, then for the equally x 2 1 = x 2 to be true the value of ‘a’ must be options 0 2 1 1/4

Question

Y RAJYALAKSHMI · Answer

The extreme points are attained at f ’(x) = 0 => 6x 2 – 18ax + 12a 2 = 0 => x = 2a, a f ’’(x) = 12x – 18a f ’’(x) 0 if x = 2a Hence the min at x = 2a = x 1 & max at x = a = x 2 The condition that x 1 2 = x 2 => (2a) 2 = a => 4a 2 – a = 0 => a = 0 or a = 1/4 Ans: 0, 1/4

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Suppose x 1 & x 2 are the point of maximum and the point of minimum respectively of the function f(x) = 2x 3 – 9ax 2 + 12a 2 x + 1 respectively, then for the equally x 2 1 = x 2 to be true the value of ‘a’ must be options 0 2 1 1/4

Suppose x₁ & x₂ are the point of maximum and the point of minimum respectively of the function f(x) = 2x³ – 9ax² + 12a²x + 1 respectively, then for the equally x²₁ = x₂ to be true the value of ‘a’ must be

options

0

2

1

1/4

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Suppose x 1 & x 2 are the point of maximum and the point of minimum respectively of the function f(x) = 2x 3 – 9ax 2 + 12a 2 x + 1 respectively, then for the equally x 2 1 = x 2 to be true the value of ‘a’ must be options 0 2 1 1/4

Suppose x1 & x2 are the point of maximum and the point of minimum respectively of the function f(x) = 2x3 – 9ax2 + 12a2x + 1 respectively, then for the equally x21 = x2 to be true the value of ‘a’ must be options 0 2 1 1/4

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Suppose x₁ & x₂ are the point of maximum and the point of minimum respectively of the function f(x) = 2x³ – 9ax² + 12a²x + 1 respectively, then for the equally x²₁ = x₂ to be true the value of ‘a’ must be

options

0

2

1

1/4