Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Someone please help me with the question 28................

Someone please help me with the question 28................

Question Image
Grade:12

1 Answers

Arun
25763 Points
2 years ago
∫ logx / (x+1)^2 dx 
= (logx) ∫ dx / (x+1)^2 - ∫[d/dx(logx) ∫dx/(x+1)^2] dx 
= - (logx) / (x+1) + ∫dx / [x(x+1) 
= - (logx) / (x+1) + ∫dx /x - ∫dx/(x+1) 
= - (logx) / (x+1) + logx - log(x+1) + c 
= log [x/(x+1)] - (logx) / (x+1) + c. 
 
 
Regards
Arun

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free