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Grade: 12
        
Someone please help me with the question 28................
one month ago

Answers : (1)

Arun
16186 Points
							
∫ logx / (x+1)^2 dx 
= (logx) ∫ dx / (x+1)^2 - ∫[d/dx(logx) ∫dx/(x+1)^2] dx 
= - (logx) / (x+1) + ∫dx / [x(x+1) 
= - (logx) / (x+1) + ∫dx /x - ∫dx/(x+1) 
= - (logx) / (x+1) + logx - log(x+1) + c 
= log [x/(x+1)] - (logx) / (x+1) + c. 
 
 
Regards
Arun
one month ago
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