Grade 12Integral Calculus
Someone please help me with the question 28................
Someone please help me with the question 28................
1 Answer
Arun
∫ logx / (x+1)^2 dx
= (logx) ∫ dx / (x+1)^2 - ∫[d/dx(logx) ∫dx/(x+1)^2] dx
= - (logx) / (x+1) + ∫dx / [x(x+1)
= - (logx) / (x+1) + ∫dx /x - ∫dx/(x+1)
= - (logx) / (x+1) + logx - log(x+1) + c
= log [x/(x+1)] - (logx) / (x+1) + c.
= (logx) ∫ dx / (x+1)^2 - ∫[d/dx(logx) ∫dx/(x+1)^2] dx
= - (logx) / (x+1) + ∫dx / [x(x+1)
= - (logx) / (x+1) + ∫dx /x - ∫dx/(x+1)
= - (logx) / (x+1) + logx - log(x+1) + c
= log [x/(x+1)] - (logx) / (x+1) + c.
Regards
Arun
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