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Solve the following integration:Q. ?{(x^2+3)/(x^6 (x^2+1))} dx
Integral{ (x2+3)/x6(x2+1)}dxIntegral {(x2+1)+2}/x6(1+x2) dxintegral dx/x6 + integraldx/x6(1+x2)(x-5)/(-5) +integral{ sec2@/tan^6@(1+tan^2@)}d@ by putting x=tan@-(1/5)x-5+integral cot6@ d@Now integrate second integral by Reduction formulaintegarl cotn@ d@= -cotn-1@/(n-1) -integral cotn-2@d@Now do yourself.........Thanks & RegardsRinkoo GuptaAskIITians Faculty
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