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Solve the following integral. .............................

Solve the following integral. .............................

Question Image
Grade:12

1 Answers

venkat
105 Points
3 years ago
use the formula of sin3x=3sinx-4sin3x
Then the integral reduces to
\int dx/(3-4sin^{2}x)
now multiply and divide with sec2x
\int sec^{2}xdx/(3sec^{2}x-4tan^{2}x)
\int sec^{2}xdx/(3+3tan^{2}x-4tan^{2}x)
\int sec^{2}xdx/(3-4tan^{2}x)
Now put tanx=t
dt=sec2xdx
\int dt/(3-4t^{2})
Use the identity and evaluate the answer.
Hope this will help you and please approve my answer
 
 
 

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