# Solve the following integral. .............................

venkat
105 Points
4 years ago
use the formula of sin3x=3sinx-4sin3x
Then the integral reduces to
$\int dx/(3-4sin^{2}x)$
now multiply and divide with sec2x
$\int sec^{2}xdx/(3sec^{2}x-4tan^{2}x)$
$\int sec^{2}xdx/(3+3tan^{2}x-4tan^{2}x)$
$\int sec^{2}xdx/(3-4tan^{2}x)$
Now put tanx=t
dt=sec2xdx
$\int dt/(3-4t^{2})$
Use the identity and evaluate the answer.