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Solve the following integral. .............................

Ashok Eswar , 7 Years ago
Grade 12
anser 1 Answers
venkat
use the formula of sin3x=3sinx-4sin3x
Then the integral reduces to
\int dx/(3-4sin^{2}x)
now multiply and divide with sec2x
\int sec^{2}xdx/(3sec^{2}x-4tan^{2}x)
\int sec^{2}xdx/(3+3tan^{2}x-4tan^{2}x)
\int sec^{2}xdx/(3-4tan^{2}x)
Now put tanx=t
dt=sec2xdx
\int dt/(3-4t^{2})
Use the identity and evaluate the answer.
Hope this will help you and please approve my answer
 
 
 
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Last Activity: 7 Years ago
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