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Grade 6Integral Calculus

solve question number 3,4,5,6.........................................................

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Profile image of vivek
10 Years agoGrade 6
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1 Answer

Profile image of vinay
10 Years ago
I would only give the hints as you could do these questions
 
For qts.4 ::
between interval (0,1) 
integral is zero as
 [ x ] =0
between interval (1,2)
integral is 3 as 
[ x ] =1
 
For qts5::
IN   2^x use x=[x] +fractional   x
 
and interval (0,{x}) ==(0,x)
 
For qts6::
in fractional part graph 
 
so sum of areas of 4 triangles between (0,4)