badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

sir please tell what is the integration of sin9x / sinx?

4 years ago

Answers : (1)

jagdish singh singh
173 Points
							
\hspace{-0.6 cm}\int\frac{\sin 9x}{\sin x}dx = \int\frac{\sin 9x-\sin 7x+\sin 7x-\sin 5x+\sin 5x-\sin 3x+\sin 3x-\sin x+\sin x}{\sin x}$\\\\\\Using $\sin C-\sin D=2\cos \frac{C+D}{2}\sin \frac{C-D}{2}$\\\\\\So $\int\frac{\sin 9x}{\sin x}dx = \int \left(\cos 8x+\cos 6x+\cos 4x+\cos 2x+1\right)dx$\\\\\\So $\int\frac{\sin 9x}{\sin x}dx = \frac{\sin 8x}{8}+\frac{\sin 6x}{6}+\frac{\sin 4x}{4}+\frac{\sin 2x}{2}+x+\mathcal{C}$
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details