Grade 12Mechanics

sinx.log(sinx)dx=log2-1
Limit of integration:0 to pi/2

Venu Choudhary

7 Years agoGrade 12

2 Answers

Saurabh Koranglekar

7 Years ago

Dear student

Please ask a question

Phanindra

7 Years ago

Put sinx = t... (1)then limits also will change...

Lower limit = 0 and upper limit = 1

Now.. differentiate (1) that is cosxdx=dt so..

dx = dt/cosx = $dt/\sqrt{}(1-t^2)$ …

Because ...sin²x + cos²x = 1...cosx = $\sqrt{}(1-t^2)$ …

Now the question chages and its limits are...0 and 1...

Hope you have understood the steps...

This is the procedure...

You will get the answer..

If you do not get the answer..then tell me.i will send the full solution..

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sinx.log(sinx)dx=log2-1Limit of integration:0 to pi/2

Venu Choudhary

2 Answers

Saurabh Koranglekar

Phanindra

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sinx.log(sinx)dx=log2-1
Limit of integration:0 to pi/2

A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.

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