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Grade: 12

                        

∫ sin2x / (sin5x sin3x ) dx , i tried by using sin sum formule , but after that i got stuck.

3 years ago

Answers : (1)

Arun
24742 Points
							
 

sin2x can be written as sin(5x-3x)=sin5xcos3x-sin3xcos5x

 

   sin2x/sin5x.sin3x=sin5xcos3x-sin3xcos5x/sin5xsin3x

 

   =cot3x-cot5x

 

  integral of cot3x-cot5x=(1/3) logsin3x  -  (1/5) logsin5x+ c

Hope it helps

3 years ago
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