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Grade: 12 

                        
∫ sin2x / (sin5x sin3x ) dx , i tried by using sin sum formule , but after that i got stuck.
3 years ago

Answers : (1)

Arun
24742 Points 
							
 
sin2x can be written as sin(5x-3x)=sin5xcos3x-sin3xcos5x
 
   sin2x/sin5x.sin3x=sin5xcos3x-sin3xcos5x/sin5xsin3x
 
   =cot3x-cot5x
 
  integral of cot3x-cot5x=(1/3) logsin3x  -  (1/5) logsin5x+ c
Hope it helps
3 years ago
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