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Integral Calculus> ∫sin2x/cos 2 x dx...

question mark

∫sin2x/cos²x dx

Lovey , 10 Years ago

Grade 12

1 Answers

Jitender Singh

Last Activity: 10 Years ago

Ans:
Hello Student,
Please find answer to your question below

$I = \int \frac{sin2x}{cos^{2}x}dx$
$cos^{2}x = t$
$2cosx(-sinx)dx = dt$
$-sin2xdx = dt$
$I = \int \frac{-1}{t^{2}}dt$
$I = \frac{1}{t} + c$
$I = \frac{1}{cos^{2}x} + c$
$I = sec^{2}x + c$

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