help@askiitians.com

+91-87964 74404

Grade Select GradeIntegral Calculus

Q . THE AREA ENCLOSED BETWEEN THE CURVES -
y = ln ( x + e ) and x = ln ( 1/y ) AND
X-AXIS.

Bharat Makkar

11 Years agoGrade Select Grade

2 Answers

Jitender Singh

Approved Tutor Answer11 Years ago

Ans:
Hello Student,
Please find answer to your question below

$y = ln(x+e)$
Intersect x-axis at (1-e, 0) & y-axis at (0, 1)
$y = e^{-x}$
Intersect y-axis at (0, 1).
Area A b/w two curves is:
$A = \int_{1-e}^{0}ln(x+e)dx + \int_{0}^{\infty }e^{-x}dx$
$A = \int_{1-e}^{0}ln(x+e)dx + 1$
$A = [eln(x+e)-x]_{1-e}^{0} + 1$
$A = [e-(-(1-e))] + 1$
$A =2$

Bharat Makkar

11 Years ago

thanks sir......and happy diwali.......

The area of a square field is 640000cm².what is its area in hectares

integral calculus

1 Answer Available

Last Activity: 3 Years ago

Please solve this integration. I am facing difficulty in it
How to solve this. Please solve anyone. Humble request

integral calculus

1 Answer Available

Last Activity: 4 Years ago

Using laplace transform, solve d²y/dt²+ dy/dt = t² +2t given that y=4 and y’=-2 and t=0

integral calculus

1 Answer Available

Last Activity: 4 Years ago

If 4th term of an A.p is zero, show that the 8th term is double the 6th term

integral calculus

1 Answer Available

Last Activity: 4 Years ago

View all Questions