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Q.27 integral calculus answer fast ................
let y=f-1(x) so that x=f(y) or dx=f’(y)dy. so when x=a, y=b and x=0, y=0so, we have to find P= ∫0toa f(x)dx+∫0toa yf’(y)dyapply integration by parts on the second integral,so that P= ∫0toa f(x)dx+ yf(y)|0toa – ∫0toa f(y)dy=af(a) – 0=ab
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