Q.241st OR question only.reply as soon as possibe please..
Q.24
1st OR question only.
reply as soon as possibe please..
Asiya Anas , 5 Years ago
Grade 12
Integral Calculus> Q.24 1 st OR question only. reply as soon...
3 Answers
Aditya Gupta
it is not clear which ques u r asking. i am assuming it is the following:
vectors 2i – 3j + 4k and – 4i + 6j – 8k are..........
note that – 4i + 6j – 8k= – 2(2i – 3j + 4k)
hence, they are collinear. but more specifically, they are anti parallel vectors, bcoz they are opposite in direction.
KINDLY APPROVE THE ANSWER PLZZ :))
Arun
Dear student
In 24 question
Take log (1 +x/1-x) = t
Then dx/(x² -1 ) = dt
Hence it becomes integration of 1 = t + constant
= Log (1 +x/1-x) + constant
Hope it helps
Aditya Gupta
oops sorry u mean to ask about integrate from 0 to pi/4 (x^2+sin^2x)/(1+x^2) dx.
separate it as integral from 0 to pi/4 (x^2)/(1+x^2) dx + integral from 0 to pi/4 (sin^2x)/(1+x^2) dx
clearly integral from 0 to pi/4 (x^2)/(1+x^2) dx is elementary.
but integral from 0 to pi/4 (sin^2x)/(1+x^2) dx is NOT POSSIBLE TO CALCULATE. the ques is wrong.
Approved Last Activity: 5 Years ago
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