Integral Calculus> prove that integration of 1/x is logx. ho...

prove that integration of 1/x is logx.

how should i prove that..

suresh pant , 9 Years ago

Grade 12th pass

2 Answers

parchan

this is based on knowledge of differntiaton.as 1/x is of the form of x**-1.differntiation in a nutshell is the opposite of integration. so as d/dx of ln(x) is 1/x.hence integral of 1/x is ln(x).

idk how to prove it

get rekt

Last Activity: 9 Years ago

Ritika Das

(ln(x))' = lim(d->0) [ ln(x+d) - ln(x) ] / d = lim ln((x+d)/x) / d
= lim (1/d) ln(1 + d/x) = lim [ ln (1 + d/x)(1/d) ].
Set u=d/x and substitute:
lim(u->0) [ ln (1 + u)(1/(ux)) ] = 1/x ln [ lim(u->0) (1 + u)(1/u) ]
= 1/x ln (e)
and since ln(e) = 1
(ln(x))' = 1/x.
and since integration is just the reverse of differentiation, then the integration of 1/x is simply ln(x)

Last Activity: 8 Years ago