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Grade 12th passIntegral Calculus

Problem number 18...
Im getting rhs as 14{x}
Answer i'm getting is x lies between -14 to 0

Question image for Problem number 18... Im getting rhs as 14{x} Answ
Profile image of Praveen Kumar Das
4 Years agoGrade 12th pass
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

It sounds like you're working through a problem involving inequalities, and it seems like you're trying to solve for the variable \( x \). Let's break down the steps to clarify how you arrived at the right-hand side (RHS) being \( 14x \) and how to interpret the solution you found, which indicates that \( x \) lies between -14 and 0.

Understanding the Inequality

First, let's assume you have an inequality that looks something like this:

  • For example: \( 14x < 0 \)

This means you want to find the values of \( x \) that make this inequality true. To solve it, you would isolate \( x \) on one side.

Step-by-Step Solution

Here’s how you can solve \( 14x < 0 \):

  1. Divide both sides of the inequality by 14. Remember, since 14 is positive, the direction of the inequality remains the same:
    • \( x < 0 \)
  2. This tells us that \( x \) must be less than 0.

Considering the Range

Now, if you mentioned that \( x \) lies between -14 and 0, it suggests that there might be another part of the problem that sets a lower limit for \( x \). For instance, if you had a different inequality like:

  • For example: \( 14x > -14 \)

In this case, you would solve it as follows:

  1. Divide both sides by 14:
    • \( x > -1 \)

Combining the Results

Now, if you combine both inequalities, \( -14 < x < 0 \) would be the solution set. This means that \( x \) can take any value greater than -14 but less than 0.

Visualizing the Solution

To visualize this, you can think of a number line:

  • Draw a line and mark the points -14 and 0.
  • Shade the region between these two points, indicating that all values in this range are valid solutions.

Final Thoughts

In summary, if your RHS is \( 14x \) and you found that \( x \) lies between -14 and 0, it suggests that you are dealing with a compound inequality or two separate inequalities that you combined. Always remember to check the signs when dividing or multiplying by negative numbers, as this can change the direction of the inequality. If you have any more specific details about the problem, feel free to share, and we can dive deeper into it!