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Plzzz solve all the 3 questions ..... I am unable to get the answer............

Unknown , 6 Years ago
Grade 12
anser 2 Answers
Vikas TU
Dear student 
Q1  Solution : Sin^-1(SinX) = X 
So, It will be Simplified to Integral (X) from (-pie/2  to pie) 
[X^2 / 2 ] limit from – pie /2 to pie 
Ans = pie^2 / 4 
= 2.50 
 
Please ask one question in a thread, 
Good Luck 
Last Activity: 6 Years ago
Aditya Gupta
once again, vikas’s answer is full of crap. correct method is as follows:
note that sin-1(sinx)= x for x belonging to – pi/2 to pi/2 and pi – x for x belonging to pi/2 to pi.
so, break the integral as
∫xdx from – pi/2 to pi/2 + ∫pi – x from x belonging to pi/2 to pi.
= 0 + pi*pi/2 – ½ *3pi^2/4
= (pi^2/2)*(1 – 3/4)
= pi^2/8, approx 1.2337
kindly approve :=)
Last Activity: 6 Years ago
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