Plz help me to solve this.....question in attachment

∫dx/(x+1)⅓+(x+1)½Let x+1=t² dx=2tdt2∫ t dt/t⅔+tLet t=z³ dt=3z²dz We get 6∫ z³ * z² dz/z² +z³ 6∫z³/1+z Dividing z³ by z+1 u will get quotient z²-z+1 and remainder -1 And you can rewrite the above expression like this given below 6∫z+1 - 1/z²-z+1You can easily integrate now