Flag Integral Calculus> Please solve this question Ans : Option 1...
question mark

Please solve this question 
Ans : Option 1 
             34 sq units
 

Myra , 5 Years ago
Grade 10
anser 2 Answers
Aditya Gupta

Last Activity: 5 Years ago

by methods of calculus we can easily write eqn of tangent as
y + 4= 2x*2
or 4x= y+4. this intersects x axis at A(1, 0). so AP by dist formula is root(17)
similarly, eqn of normal is y – 4= –1/4(x – 2) or 4y + x= 18. this intersects x axis at B(18, 0). so BP by dist formula is 4root(17).
since tangent and normal are perpendicular to each other, the area of the so formed right triangle APB is ½ * AP * BP.
or ½ *root(17)*4root(17)= 2*17
=34
kindly approve :)

Ankush Bhowmik

Last Activity: 5 Years ago

A
By using calculus we get,
Equation of tangent is 4x-y=4
Equation of normal is X+4y=18
Equation of X axis is y=0
Now, drawing the graphs simultaneously we get the bounded region which we can  divideinto two parts as the sum of two definite integrals as area such as follows
\int_{1}^{2}(4x-4)dx + \int_{2}^{18}(-1/4)(x-18)dx
Which on solving we get the area of the bounded region as 34 sq. units i.e. option a.

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...