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`        Please solve the integral problem .Definite integrals `
one year ago

```							Differentiate both sidesf'(x)= 1/f(x)Let y= f(x)So ydy= dxIntegratingy^2= 2x+CAt x=0, y=0So C=0So y=+-√(2x)Put x=1, so minus sign gets rejected.Therefore, f(x)= √(2x)
```
one year ago
```							But please explain how at X=0 y=0Please explain his step I am not getting in this step properlyMinimum hundred words are required so I am just ffgbhhhg
```
one year ago
```							The reason for x=0 and y= 0 is as followsIn the equation given in the question we havey= f(x)=∫0 to x of some function.In this equation put x equal to zero.f(0)= 0 because any integral from zero to zero obviously equals zero.
```
one year ago
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