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Grade: 10
        
Please solve the integral calculus who is appropriate answer attached with it
one year ago

Answers : (1)

Aditya Gupta
1381 Points
							
the question is quite easy actually.
we are given that ∫f(x)dx=1
integrate by parts, taking u=f(x) and v=1
so, we get 1=1-∫xf’(x)dx
or ∫xf’(x)dx=0
now integrating the above integral by parts and taking u=f’(x) and v=x, we get
2016^2/2016=∫x^2f”(x)dx
or ∫x^2f”(x)dx= 2016
one year ago
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