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Dear student Image is not clear. Please check and repost the question with a clear attachment. I will be happy to help you
with some effort we can observe that f(x)= 1 – x.so, J= ∫0 to 1 (2x – 1)^2018 dxput y= 2x – 1so 2J= ∫ – 1 to 1 y^2018 dy2J= 2*∫0 to 1 y^2018 dyJ= y^2019/2019 |0 to 1= 1/2019KINDLY APPROVE :))
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