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Grade 12th passIntegral Calculus

PLEASE SOLVE IT

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Profile image of Aakash
10 Years agoGrade 12th pass
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1 Answer

Profile image of jagdish singh singh
10 Years ago
\hspace{-0.5 cm}$ Let $\bf{I = \int\frac{x}{(1-x^2)^{\frac{3}{2}}}dx\;,}$ Now Put $\bf{(1-x^2) = t\;,}$ Then $\bf{-2xdx = dt}$\\\\\\and Changing Limit, We get $\bf{I = \frac{1}{2}\int_{0}^{1}u^{-\frac{3}{4}}du = 2\left[ u^{\frac{1}{4}}\right]_{0}^{1} = 2.}$

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