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please give me the solution for this question as soon as possible

please give me the solution for this question as soon as possible

Question Image
Grade:12

1 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
7 years ago

Dear student,

please post your question separately.


v3 cosec20 – sec 20

v3/sin20-1/cos20

=[v3cos20-sin20]/[sin20cos20]

=2[v3/2.cos20 -1/2 sin20]/sin 20cos20

=2[cos30.cos20-sin30.sin20]/sin20cos20

=2[cos(20+30)]/[sin20cos20]

=2os50/sin20cos20

=4cos50/2sin20cos20

=4cos50/sin40

=4cos(90-40)/sin40

=4sin40/sin40

=4

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

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