please explain fully …...please …...hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...

Question

Jitender Singh · Answer

Ans:
Hello Student,
Please find answer to your question below

[x] is the greatest integer that is less than or equal to x.

[x] is 0 if x lies between 0 (included) and 1 (excluded)
[x] is 1 if x lies between 1 (included) and 2 (excluded)

In this case, the xthterm is
$[\frac{3}{4}+\frac{x}{100}]$
where x varies from 0 to 99 (both included)
This will be equal to zero till the value inside is atleast 1.
Note that the last term is [3/4 + 99/100] = [1.74] = 1.
So every term will equal 1, starting from the term where 3/4+ x/100 = 1
$\frac{3}{4}+\frac{x}{100} = 1$
$x = 25$

Thus from x = 25, to x = 99, each term evaluates to 1.
And from x = 0 to x = 24, each term equal to zero.
So, the sum will be equal to: how many numbers are between 25 and 99 (both included) = 99 – 25 + 1 = 75

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please explain fully …...please …...hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...

please explain fully …...please …...hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...

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