Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

please explain fully …...please …...hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...

please explain fully …...please …...hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...

Question Image
Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
6 years ago
Ans:
Hello Student,
Please find answer to your question below

[x] is the greatest integer that is less than or equal to x.

[x] is 0 if x lies between 0 (included) and 1 (excluded)
[x] is 1 if x lies between 1 (included) and 2 (excluded)

In this case, the xthterm is
[\frac{3}{4}+\frac{x}{100}]
where x varies from 0 to 99 (both included)
This will be equal to zero till the value inside is atleast 1.
Note that the last term is [3/4 + 99/100] = [1.74] = 1.
So every term will equal 1, starting from the term where 3/4+ x/100 = 1
\frac{3}{4}+\frac{x}{100} = 1
x = 25

Thus from x = 25, to x = 99, each term evaluates to 1.
And from x = 0 to x = 24, each term equal to zero.
So, the sum will be equal to: how many numbers are between 25 and 99 (both included) = 99 – 25 + 1 = 75

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free