Yash Jain11 Years agoI = ∫ (3x3-5x2+4x-9)dx / (x2+2) = ∫ (3x-5)dx + ∫ (-2x+1)dx / (x2+2) [Simple division] = 3x2/2 – 5x – ∫ 2xdx / (x2+2) + ∫ dx / (x2+2) = 3x2/2 – 5x – log|x2+2| + 1/rt(2)*tan-1{x/rt(2)}Hope its clear.