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Grade 11Integral Calculus

Please answer the above attached question with the method used as soon as possible

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Profile image of supraja venkatraman
6 Years agoGrade 11
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1 Answer

Profile image of Arun
6 Years ago
Dear student
 
it can be wrotten as ∑r= 0 to 4n ( 1/2n+r)
 
∑r=0 to 4n  1/n (1/2+ r/n)
 
now 1/n = dx
r/n = x
 
and limit of Integration is 0 to 4
 
hence ∫0 to 4 [1/x + 2] dx
 
ln ( x + 2) from 0 to 4
 
ln 6 – ln 2 = ln (6/2) = ln 3