Flag Integral Calculus> pi/2 ∫ 0 sin x dx...
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pi/20 sin x dx

taniska , 10 Years ago
Grade 12
anser 1 Answers
Anusha

Last Activity: 10 Years ago

Ans:- pi/20 sinx dx
=[-cosx]0pi/2
=[-cos(pi/2)-(-cos0)]
=[0+1]
=1

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