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options\tx = a is a point of minimum\tx = a is a point of maximum\tx = a is not a point of maximum or minimum\tNone of these

Aditya Kartikeya , 10 Years ago
Grade 10
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
Hello Student,
Please find answer to your question below

f'(x) = (x-a)^{2n}(x-b)^{2m+1}
f''(x) = (x-a)^{2n}[(2m+1)(x-b)^{2m}] + (x-b)^{2m+1}[2n(x-a)^{2n-1}]Since
2n-1 > 0
f''(a) = (a-a)^{2n}[(2m+1)(a-b)^{2m}] + (a-b)^{2m+1}[2n(a-a)^{2n-1}]
f''(a) = (0)^{2n}[(2m+1)(a-b)^{2m}] + (a-b)^{2m+1}[2n(0)^{2n-1}]
f''(a) = 0+0
f''(a) = 0
So x = a is neither maximum nor minimum.

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