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options f(x) is bounded and it takes both of it’s bounds and the range of f(x) contains exactly one integral point. f(x) is bounded and it takes both of it’s bounds and the range of f(x) contains more than one integral point f(x) is bounded but minimum and maximum does not exists. f(x) is not bounded as the upper bound does not exist.

options
  1. f(x) is bounded and it takes both of it’s bounds and the range of f(x) contains exactly one integral point.
  2. f(x) is bounded and it takes both of it’s bounds and the range of f(x) contains more than one integral point
  3. f(x) is bounded but minimum and maximum does not exists.
  4. f(x) is not bounded as the upper bound does not exist.

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Grade:10

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
6 years ago
Hii I have attached a word format of the answer you can consider this for solving
Option A is the answer
Substitute tanx = t and write the series in terms of t,
then use (m+ 1/m) >= 2 u’ll get the values which will make it bounded.

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