options\tf(x) is bounded and it takes both of it’s bounds and the range of f(x) contains exactly one integral point.\tf(x) is bounded and it takes both of it’s bounds and the range of f(x) contains more than one integral point\tf(x) is bounded but minimum and maximum does not exists.\tf(x) is not bounded as the upper bound does not exist.

Aditya Kartikeya , 10 Years ago

Grade 10