Question icon
Grade 10Integral Calculus

options
  1. 7
  1. 3
  2. 5
  3. 1

Question image for options 7 3 5 1
Profile image of Aditya Kartikeya
12 Years agoGrade 10
Answers icon

1 Answer

Profile image of Jitender Singh
12 Years ago
Ans:
Hello Student,
Please find answer to your question below

\int_{0}^{\pi }(f(x)+f''(x))sinxdx = 5
\int_{0}^{\pi }[(f(x)+f''(x))sinx-f'(x)cosx+f'(x)cosx]dx = 5
\int_{0}^{\pi }[f(x)sinx+f''(x)sinx-f'(x)cosx+f'(x)cosx]dx = 5
\int_{0}^{\pi }[-(f'(x)cosx-sinxf(x))+sinxf''(x)+f'(x)cosx]dx = 5
\int_{0}^{\pi }-(cosxf(x))'dx+\int_{0}^{\pi }(sinxf'(x))dx = 5
[-(cosxf(x))]_{0}^{\pi }+(sinxf'(x))_{0}^{\pi } = 5
-(-f(\pi )-f(0)) = 5
f(\pi ) + f(0) = 5
2 + f(0) = 5
f(0) = 3