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Grade 10Integral Calculus

options

π/4e²

π/4e

1/e²(π/2 – tan^-1 1/e)

π/2e²

Question image for options π/4e 2 π/4e 1/e 2 (π/2 – tan -1 1/e) π/2e

Aditya Kartikeya

11 Years agoGrade 10

1 Answer

Jitender Singh

11 Years ago

Ans:
Hello Student,
Please find answer to your question below

$I = \int_{1}^{\infty }\frac{1}{e^{x+1}+e^{3-x}}dx$
$I = \int_{1}^{\infty }\frac{e^{x}}{e^{2x+1}+e^{3}}dx$
$I = \frac{1}{e}\int_{1}^{\infty }\frac{e^{x}}{e^{2x}+e^{2}}dx$
$I = \frac{1}{e}\int_{1}^{\infty }\frac{e^{x}}{(e^{x})^{2}+e^{2}}dx$
$e^{x} = t$
$e^{x}dx = dt$
$I = \frac{1}{e}\int_{e}^{\infty }\frac{1}{t^2+e^2}dt$
$I = \frac{1}{e}.[\frac{1}{e}.tan^{-1}(\frac{t}{e})]_{e}^{\infty}$
$I = \frac{1}{e^2}.[\frac{\pi }{2} - \frac{\pi }{4}]$
$I = \frac{1}{e^2}.[\frac{\pi }{4}]$
$I = \frac{\pi }{4e^2}$
Option (1) is correct.

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