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```
log(x^2+2)/(x+2)^2
log(x^2+2)/(x+2)^2

```
6 years ago

```							Integral log(x^2+2)/(x+2)^2dxintegrating by part by taking log(x^2+2) as first function and 1/(x+2)^2 as second function=>-(log(x^2+2).)/(x+2)+integral{2x/(x^2+2).(x+2)}dxusing partial fractionlet x/(x^2+2)(x+2)=A/(x^2+2)+B/(x+2)=>x=A(x+2)+B(x^2+2)put x=-2 we get-2=B(4+2)=6B=>B=-2/6=-1/3put x=00=2A+2B=>0=2A-2/3=>2A=2/3=>A=1/3Hence the solution is-(log(x^2+2))/(x+2)+2integral{1/(3(x^2+3))-1/(3(x+2))}dx=-(log(x^2+2))/(x+2)+2/3{arctan(x/root2)-logmod(x+2)}Thanks & RegardsRinkoo GuptaAskIITians Faculty
```
6 years ago
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