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Let f(x)=integration of( (2x+1)÷(x²-2x+2))du from(o,x)then find the least value of f(x) in (-1,1)

lokesh palingi , 11 Years ago
Grade 12
anser 1 Answers
Rinkoo Gupta

Last Activity: 10 Years ago

put 2x+1=A.d/dx(x^2-2x+2)+B

2x+1=A(2x-2)+B
comapring coeff of x and constant terms
2=2A amd 1=-2A+B
=>A=1 and 1=-2+B=>B=3
hence integral of (2x+1)/(x^2-2x+2)dx
=integral(2x-2)/(x^2-2x+2) .dx+3integral dx/(x^-2x+3)
=logmod(x^2-2x+2)+3integraldx/(x-1)^2+1
=logmod(x^2-2x+2)+3 arctan(x-1) +C

Thanks & Regards
Rinkoo Gupta
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