Let f:[-1, 2] → R be differentiable such that 0 ≤ f’(t) ≤ 1 for t ∈ [-1, 0] and -1 ≤ f’(t) ≤ 0 for t ∈ [0, 2]. Then options - -2 ≤ f(2) – f(-1) ≤ 1
- 1 ≤ f(2) – f(-1) ≤ 2
- - 3 ≤ f(2) – f(-1) ≤ 0
- - 2 ≤ f(2) – f(-1) ≤ 0
Let f:[-1, 2] → R be differentiable such that 0 ≤ f’(t) ≤ 1 for t ∈ [-1, 0] and -1 ≤ f’(t) ≤ 0 for t ∈ [0, 2]. Then
options
- -2 ≤ f(2) – f(-1) ≤ 1
- 1 ≤ f(2) – f(-1) ≤ 2
- - 3 ≤ f(2) – f(-1) ≤ 0
- - 2 ≤ f(2) – f(-1) ≤ 0