# Intrigate (1÷logx)-(1÷(logx)^2) upper limit e lower limit 2

$\int (1).(1/Logx)dx - \int (1/(Logx)^{2})dx$
when u would integrate this $\int (1).(1/Logx)dx$   by using part function(Taking 1 as 2nd function) , it will get cancelled(other part) and u would end up with $\int (x/Logx)dx$   THEN PUT THE LIMITS AND GET THE ANSWER