Integretion of xsinxcosx/(a²cos²+b²sin²)² dx from 0 to π/2.

Question

gopesh · Answer

first eliminate x from numerator by applying f(x)=f(a-x) for 0 to pi/2 open the whole square of denominator and divide numerator and denominator by (cosx)^4 put tan x =t and evaluate to get answer...

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Integretion of xsinxcosx/(a²cos²+b²sin²)² dx from 0 to π/2.

Integretion of xsinxcosx/(a²cos²+b²sin²)² dx from 0 to π/2.

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