Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
integration using trigonometric identetiees cos2xsinx integration using trigonometric identetiees cos2xsinx
Yaa here`s the answer to your query..Integration(sinx.cosxdx)By using the identity sinAcosB = 1/2[sin(A-B)+sin(A+B)]So, Integration(sinx.cosxdx)We get 1/2int [sin(-x) + sin3x]= 1/2 int[-sinx + sin3x]=1/2[int(-sinx) + int(sin3x)]=1/2(cosx -1/3cos3x) +C
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -