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Grade: 12 

                        
Integration of x^4/(x-1)(x^2+1)?
4 years ago

Answers : (3)

Harsh Patodia
IIT Roorkee
askIITians Faculty
907 Points 
							PFA
228-2027_6.PNG
4 years ago
mycroft holmes
272 Points 
							
We can reduce the effort substantially......


\frac{x^4}{(x-1)(x^2+1)} = \frac{x^4-1+1}{(x-1)(x^2+1)}


= \frac{x^4-1}{(x-1)(x^2+1)}+ \frac{1}{(x-1)(x^2+1)}


=x+1+ \frac{1}{2} \left( \frac{1}{x-1} + \frac{x+1}{x^2+1}\right )


This is easy to integrate
4 years ago
Kushagra Madhukar
askIITians Faculty
605 Points 
							
Dear student,
Please find the attached solution to your problem.
\frac{x^4}{(x-1)(x^2+1)} = \frac{x^4-1+1}{(x-1)(x^2+1)} = \frac{x^4-1}{(x-1)(x^2+1)}+ \frac{1}{(x-1)(x^2+1)}
=x+1+ \frac{1}{2} \left( \frac{1}{x-1} + \frac{x+1}{x^2+1}\right )
Now integraing, we get,
x2/2 + x + 1/2( ln(x – 1) + 1/2ln(x2 + 1) + tan-1(x))
 
Hope it helps.
Thanks and regards,
Kushagra
4 months ago
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