# Integration of sin inverse x upon x from 0 to pi by 2

Phanindra
226 Points
5 years ago
I think the limits are 0 to 1...
If the li ite0s are 0 to 1...then you will get ans....(pie/2) - 1....
If the limits are 0 to (pie/2) then also u wil get the answer but it is complicated...
Here...In this question use by parts rule..
Take sin inverse x as first function...and 1 as second function...
By parts formula is....
f(x)∫g(x) - ∫ f'(x)∫g(x) dx...
Here...f(x) is first function and g(x) is second function...