MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        Integration of sin inverse x upon x from 0 to pi by 2
9 months ago

Answers : (1)

Phanindra
222 Points
							
I think the limits are 0 to 1...
If the li ite0s are 0 to 1...then you will get ans....(pie/2) - 1....
If the limits are 0 to (pie/2) then also u wil get the answer but it is complicated...
Here...In this question use by parts rule..
Take sin inverse x as first function...and 1 as second function...
By parts formula is....
f(x)∫g(x) - ∫ f'(x)∫g(x) dx...
Here...f(x) is first function and g(x) is second function...
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 170 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details