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Integrate( x^2+2x +1 )with respect to dx having limit 0 to 1. Can we solve it like these. If no why not.I am getting two different answer by twio diff. Method , one given in the photo and the one below:- When you integrate the above term you will get |x^3/3 + x^2 + x| limit 0 to 1....Now when you will put the limit from 0 to1 you will get1/3 + 1 + 1 =7/3...Which one is correct . explain with reason .pls urgent.

Integrate( x^2+2x +1 )with respect to dx having limit 0 to 1. Can we solve it like these. If no why not.I am getting two different answer by twio diff. Method , one given in the photo and the one below:- When you integrate the above term you will get |x^3/3 + x^2 + x| limit 0 to 1....Now when you will put the limit from 0 to1 you will get1/3 + 1 + 1 =7/3...Which one is correct . explain with reason .pls urgent.

Question Image
Grade:12

1 Answers

Chandan
121 Points
3 years ago
in the second method (in the attachment) you surely put the upper limit as 1 but forgot to subtract the lower limit
in this case lower limit is not zero if you put x=0 you get lower limit 1/3 
hence answer is 8/3-1/3=7/3
hope it is clear
thankyou
goodday

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