Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Integrate - x^2+1/x^2-5x+6 by using partial fraction method of integration.

Integrate - x^2+1/x^2-5x+6 by using partial fraction method of integration.

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Here the integrand is not a proper rational function ,so we divide x2+1 by x2-5x+6
x2+1/x2-5x+6 =1+(5x-5)/x2-5x+6 = 1+(5x-5)/(x-2)(x-3)
(5x-5)/(x-2)(x-3) = A/x-2+B/X-3
5x-5=A(x-3)+B(x-2)
equate the coefficients of constant terms and x on both sides ,you will get A+B=5 and 3A+2B=5 .Solve these equations then A=-5 AND B=10
(X2+1)/X2-5X+6 =1-5/X-2+10/X-3
∫(x2+1)/x2-5x+6 =∫dx-5∫1/x-2 dx+10∫dx/x-3
=x-5 log modulus(x-2) +10log(x-3)+c

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free