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At the first taking expression and simplyfing it..
(x^2+1)/x^4+x^2+1
Dividing by x^2 in numerator and denominator. So it's become
=1+1/x^2 whole divided by x^2+1+1/x^2
=(1+1/x^2)/(x^2+1/x^2-2)+2+1
=(1+1/x^2)/(x-1/x)^2+3
So from question-
Int. (1+1/x^2) dx/(x-1/x)^2+3__________A
Taking (x-1/x)= t
Differentiating ‘x' with respect to ‘t'
1+1/x^2 dx = dt putting this value in equation no.A we get
=Int. {dt/t^2+(√3)^2}
= 1/√3 tan^-1 (t/√3)
again putting the value of ‘t'
= 1/√3 tan^-1 (x-1/x)/√3
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