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Grade 12th passIntegral Calculus

Integrate the following question
log(1/z)3 limits are -1 to +1

Profile image of Mary
8 Years agoGrade 12th pass
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1 Answer

Profile image of Anish Singhal
8 Years ago
Limits cant be negative in this.
log (1/z)^3 is nothing but -3logz and then if you integrate it by using byparts you will get (zlogz-z) limits from -1 to 1. Hence at -1 it is not defined