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Integrate the following question log(1/z) 3 limits are -1 to +1 Integrate the following question log(1/z)3 limits are -1 to +1
Limits cant be negative in this.log (1/z)^3 is nothing but -3logz and then if you integrate it by using byparts you will get (zlogz-z) limits from -1 to 1. Hence at -1 it is not defined
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