Question icon
Grade 12Integral Calculus

integrate the following integral
∫ sin^2 bx dx

Profile image of taniska
11 Years agoGrade 12
Answers icon

1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:
Hello Student,
Please find answer to your question below

I = \int sin^{2}bxdx
I = \frac{1}{2}\int 2sin^{2}bxdx
I = \frac{1}{2}\int (1-cos2bx)dx
I = \frac{1}{2}\int dx-\frac{1}{2}\int cos2bxdx
I = \frac{x}{2}-\frac{1}{2}\int cos2bxdx
I = \frac{x}{2}-\frac{1}{4b}sin2bx+c