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Grade: 11
        
integrate the following function. how to solve this type of questions
 1/(a+bsinx)
2 years ago

Answers : (1)

Aravind Suresh
34 Points
							First take 1/a common .=1/(1+b/a sinx)Now multiply and divide by (1-b/a sinx)Now the denominator is (b/a cosx)^2=» (1-b/a six)/(b/a cosx)^2One becomes secx^2 and other is tanxsecx.
						
2 years ago
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