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integrate the following function. how to solve this type of questions
1/(a+bsinx)

Sudeesh Patel , 9 Years ago
Grade 11
anser 1 Answers
Aravind Suresh
First take 1/a common .=1/(1+b/a sinx)Now multiply and divide by (1-b/a sinx)Now the denominator is (b/a cosx)^2=» (1-b/a six)/(b/a cosx)^2One becomes secx^2 and other is tanxsecx.
Last Activity: 9 Years ago
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