Nandana
Last Activity: 7 Years ago
hi !
here,
Y = ∫xtanxsec2 x dx
take,
U = x dV =tanxsec2 x dx
dU =1 V = ∫ tanx sec2 x dx
y = tanx
dy = sec2 x dx
V = ∫ y dy = y2 /2 = tan2 x /2
Y = ½ x tan2 x – ½ ∫ tan2 x dx
= ½ (xtan2 x – ∫(sec2 x -1)dx)
Y = ½ xtan2 x + x- tanx is the answer !