Integrate itPlease reply soon!!!!!!!!!!!!!!!!!!!!!!!

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Ritika Das · Answer

Let u = tan x. du/dx = sec 2 x. dx = (1/sec 2 x).du. I = ∫(sec x) x /(sqrt(tan x)).dx Now replacing tan x with u and dx with (1/sec 2 x).du we get I: – I = ∫(sec x) x /(sqrt(u)).du.(1/sec 2 x). = sec x – 2 x∫u -1/2 .du. = 2sec x – 2 x.u 1/2 + c Replacing u with tan x, I = 2sec x – 2 x.(sqrt(tan x)) + c. Please approve my answer if you liked the explanation!

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Integrate itPlease reply soon!!!!!!!!!!!!!!!!!!!!!!!

Integrate itPlease reply soon!!!!!!!!!!!!!!!!!!!!!!!

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