Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Integrate from 0 to 1. ∫|sin2(pi)x| dx || is a modulus function.

Integrate from 0 to 1.
∫|sin2(pi)x| dx
|| is a modulus function.

Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
6 years ago
Ans:
Hello Student,
Please find answer to your question below

I = \int_{0}^{1}|sin(2\pi )x|dx
I = \int_{0}^{\frac{1}{2}}(sin(2\pi )x)dx+\int_{1/2}^{1}(-sin(2\pi x))dx
I = \frac{-cos(2\pi x)}{2\pi }|_{0}^{1/2} + \frac{cos(2\pi x)}{2\pi }|_{1/2}^{1}
I = \frac{2}{2\pi } + \frac{2}{2\pi }
I = \frac{4}{2\pi } = \frac{2}{\pi }

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free