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Integrate:(e^x/1+e^x)dx For upper limit log2 lower limit 0

Integrate:(e^x/1+e^x)dx For upper limit log2 lower limit 0

Grade:12th pass

1 Answers

Chandan
121 Points
4 years ago
Take (e^x) as t(e^x)dx= dttherefore the value of the integral is log(1+e^x)Putting limitsAnd is log((1+e^2)/2))

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