Grade 12Integral Calculus

integrate 1/ sincubex- coscubex

keshav kr

12 Years agoGrade 12

12 Years ago

$\int \frac{1}{ Sin[x]^3 - Cos[x]^3}dx$

$-(1/8) Cosec[x/2]{2} - 1/2 Log[Cos[x/2]] + 1/2 Log[Sin[x/2]] + 1/8 Sec[x/2]^{2} - (3 Sin[x])/4 - 1/12 Sin[3 x]$

12 Years ago

how u have given this ans plz rectify it dont post wrong ans plz

12 Years ago

dear it is sin cube x not sin x cube and similarly in cos also

integral calculus

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integral calculus

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integral calculus

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integral calculus

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